Derive most trigonometric identities from the addition formulas

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SUMMARY

The discussion focuses on deriving trigonometric identities from addition formulas, specifically the difference of sines and cosines. The formula for the difference of sines is given as \(\sin{a}-\sin{b}=2\cos{\frac{a+b}{2}}\sin{\frac{a-b}{2}}\). The derivation involves substituting \(a = c + d\) and \(b = c - d\), leading to the conclusion that the identities can be simplified by considering \(a\) and \(b\) as equidistant from an intermediate value. This method reduces the need for memorization of trigonometric identities.

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  • Understanding of trigonometric functions and identities
  • Familiarity with addition and subtraction formulas for sine and cosine
  • Basic algebraic manipulation skills
  • Knowledge of arithmetic means in trigonometry
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hypermonkey2
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In the same way that it is possible to derive most trigonometric identities from the addition formulas, what is the way that the difference of sines and cosines formulas were derived, such as

[tex]\sin{a}-\sin{b}=2\cos{\frac{a+b}{2}}\sin{\frac{a-b}{2}}[/tex]

thanks, I am trying to avoid as much memorization as possible, if anyones wondering.
 
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Take a = c + d and b = c - d for arithmetic mean c. Now substitute sinc+d and subtract sinc-d form it. the sind*cosc have opposite signs in bot the formula. so the answer is 2sind*cosc which when substituted you get above result.
similarly you can do for sina + sinb and addition as well as subtraction for cos as well as tan.
 
interesting! so the trick is to suppose that a and b are at equal distance from an intermediate value, correct? Very nice solution, thanks.
 

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