Derive relations for components by rotation of axes

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SUMMARY

The discussion focuses on deriving the transformation equations for the components of a two-dimensional vector \( r \) when the coordinate axes are rotated by an angle \( \Theta \). The established relations are \( x1' = \cos\Theta \cdot x1 + \sin\Theta \cdot x2 \) and \( x2' = -\sin\Theta \cdot x1 + \cos\Theta \cdot x2 \). The user attempts to validate these transformations by considering the rotation of the unit vectors (1,0) and (0,1) in the Cartesian plane, utilizing trigonometric principles to illustrate the relationship between the original and rotated coordinates.

PREREQUISITES
  • Understanding of two-dimensional vectors
  • Familiarity with trigonometric functions (sine and cosine)
  • Knowledge of coordinate transformations
  • Basic principles of linear algebra
NEXT STEPS
  • Study the derivation of rotation matrices in linear algebra
  • Explore applications of coordinate transformations in physics
  • Learn about the geometric interpretation of vector rotations
  • Investigate the implications of rotation in higher dimensions
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who are working with vector transformations and coordinate systems will benefit from this discussion.

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Homework Statement



x1,x2) are the components of a 2 dimensional vector r when referred to cartesian axes along the directions i,j. derive the relations
x1'= cosΘ x1+sinΘ x2
x2'=-sinΘ x1+cosΘ x2
for the components (x1',x2') or r referred to new axes i',j' obtained by a rotation of the axes through an angle Θ about the k direction


Homework Equations





The Attempt at a Solution


i just wrote that r=x^2+y^2 which in this case would be x1^2+x2^2 and then accounted for rotation by multiplying by sin or cos theta and proving that x1^2+x2^2=x1'^2+x2'^2 but it don't think its sufficient
 
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What's (1,0) rotated by an angle theta? Ditto for (0,1). To get those just draw a right triangle in the xy plane with angle theta at the origin. Use trig. Then (x1,x2)=x1*(1,0)+x2*(0,1).
 

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