Deriving and Integrating Terminal Velocity Equation for Position

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SUMMARY

The discussion centers on the derivation and integration of the terminal velocity equation, specifically the equation (dv_y)/(v_y+v_t) = (k/m)(dt). Here, v_y represents the y velocity, v_t is the terminal velocity, k is the fluid resistance constant, m is mass, and t is time. The user seeks clarification on the limits of integration, questioning the use of two velocities (v_y and v_t) and the necessity of limits in the integration process. It is established that integrating the provided differential will yield velocity as a function of time rather than position.

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  • Understanding of differential equations
  • Familiarity with the concept of terminal velocity
  • Basic knowledge of integration techniques
  • Awareness of fluid dynamics principles
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(dv_y)/(v_y+v_t) = (k/m)(dt) where v_y is y velocity, v_t is terminal velocity, k is fluid resistance constant, m is mass and t is time

This is my equation I derived for terminal velocity. I am going to integrate it for a function for position.

In my text, the limits of integration on the left side are written as V and 0. Right side is t and 0.

Could someone clear up the limits here? Like, there are 2 vs, v_y and v_t..what v is the limit referring to here? And I am a bit confused as to why the limits are needed here? I understand integration, but I am fairly new to it, maybe that's why!
 
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Integrating the differential you have there won't give to position as a function of time, it will give you velocity as a function of time.
 

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