Deriving equation for force from pressure that varies with water level

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 6K views
cientifiquito
Messages
7
Reaction score
0

Homework Statement



Water is filled to a height H behind a dam of width w. Determine the resultant force exerted by the water on the dam.

Homework Equations



P=pgh = pg(H-y) (where p is density, greek rho)

dF = PdA = pg(H-y)wdy (where dA is a narrow horizontal strip of the dam with area wdy and dy is delta y, the change in height)

F = antiderivative (PdA) which is [pg(H-y)wdy] bounded by H and 0.

The Attempt at a Solution



The solution is 1/2pgwH^2, but I don't understand how to do the integration. In fact, it's not even a problem, it's an example (and I'm on break between semesters) but the fact that I can't remember how to take the integral is bothering me. If anyone can make sense of my ascii attempt to copy the steps, and then explain it, I'll really appreciate it.

Thanks.
 
Physics news on Phys.org
p,g,w are constants, you can take them outside the integral. Then you are left with (H-y)dy. That's pretty straightforward, just take the antiderivative of each term, with respect to y. Does that help?
 
Yes, thanks hage567.