Deriving Hubble redshift in closed Universe from Maxwell equations

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 2K views
inline
Messages
14
Reaction score
0

Homework Statement


I should derive the Hubble law redshift from Maxwell equations in closed Universe.

Homework Equations


The metric of closed Universe is [tex]ds^2 = dt^2 - a^2(t)\left(d\chi^2 + \sin^2 \chi d\theta^2 + \sin^2 \chi \sin^2 \theta d\phi^2\right)[/tex].
The Hubble law redshift: [tex]\frac {\lambda(t)} {\lambda(t_0)} = \frac {a(t)} {a(t_0)}[/tex].
The wave equation for 4-potential is
[tex]\nabla_\mu F^{\mu\nu} = 0 \Rightarrow \partial_\mu \left(\sqrt{-g}g^{\mu\rho}g^{\nu\sigma}\left(\partial_\rho A _\sigma - \partial_\sigma A_\rho\right)\right)[/tex]

The Attempt at a Solution


As you can see the wave equation is very difficult to solve. Is there another way to show the Hubble redshift low for electormagnetic waves using Maxwell equations?
 
Last edited:
Physics news on Phys.org