Deriving Law of Conservation of Energy from E=MC2

  • Thread starter superdirt
  • Start date
9
0
Hello,

First post. Thank you for letting me be a part of the discussion.

My question is, can the Law of Conservation of Energy, http://upload.wikimedia.org/math/2/7/3/273abc16486177bf6cc4c8ec4a4a5fc9.png, be derived using E=MC2.

I understand that the E=MC2 can be derived using the LoCE and other formulas, but my question is, can the LoCE be derived from E=MC2 and other necessary formulas. My calculus is not so good these days, but my intuition says that the answer is yes and this is a relatively easy proof.

This question is a part of a larger thought experiment of mine.

Thanks,

Scott
 

pam

455
1
If "E=MC2 can be derived using the LoCE and other formulas", then writing the steps backwards you can derive the converse. This is true for any derivation.
 

George Jones

Staff Emeritus
Science Advisor
Gold Member
7,231
785
If "E=MC2 can be derived using the LoCE and other formulas", then writing the steps backwards you can derive the converse. This is true for any derivation.
This depends on what one means by "derivation", and I guess we use different definitions.

I would say that if a derivation is a tautology, then the derivation can be reversed.

For example, I would say that

[tex]A \Leftrightarrow B \Leftrightarrow C[/tex]

is a derivation of [itex]C[/itex] from [itex]A[/itex] that can be reversed, while

[tex]A \Rightarrow B \Leftrightarrow C[/tex]

is a derivation of [itex]C[/itex] from [itex]A[/itex] that can't, necessarily, be reversed.
 
249
0
Hello,

I understand that the E=MC2 can be derived using the LoCE and other formulas, but my question is, can the LoCE be derived from E=MC2 and other necessary formulas.

Scott
As I see it both derivations are the same:

1. We find a new experiment where LoCE seems to fail
2. We define a new energy so that LoCE is respected again

Consequences:

If the energy has the defined form, then LoCE is respected.
If LoCE is respected, then energy must have the defined form.
 
E=mcc

Hello,

First post. Thank you for letting me be a part of the discussion.

My question is, can the Law of Conservation of Energy, http://upload.wikimedia.org/math/2/7/3/273abc16486177bf6cc4c8ec4a4a5fc9.png, be derived using E=MC2.

I understand that the E=MC2 can be derived using the LoCE and other formulas, but my question is, can the LoCE be derived from E=MC2 and other necessary formulas. My calculus is not so good these days, but my intuition says that the answer is yes and this is a relatively easy proof.

This question is a part of a larger thought experiment of mine.

Thanks,

Scott
As far as I know E=mcc can be derived without usin conservation of energy
 
249
0
I have thought of an experiment that (for one simple geometry) derives LoCE from E=mc^2
(or inversely):

You connect two weights with a light stick and fix it into a box so that they can rotate in one plane. Then you close the box and try to accelerate it.
If you calculate the required force of acceleration, it turns out that it is more difficult to accelerate the box if the weights inside are rotating. If the mass of the all box parts is m and kinetic energy of the rotating weights is T, then the required force is:

F=(m+T/c^2)*a

So anyone who would try to determine the mass of the closed box would measure:

M=m+T/c^2

If the box would be taken to pieces, then the total mass would decrease by:

dM=-T/c^2

While the kinetic energy T would emerge.

Conclusion: the conservation of energy is respected only if we set:

dE=dM*c^2
 
Last edited:

clem

Science Advisor
1,308
15
249
0
I think this implicitly assumes E=mc^2 to prove E=mc^2.
No, because I calculated force as the time derivative of relativistic momentum (and relativistic momentum can be derived from Lorentz transformation (and Newton's law), no need for E=mc^2).
I also used the formula T=m*(gama-1)*c^2. This formula seems derived from E=m*gama*c^2, but it is in fact the other way round: T can be derived by integrating accelerating force over acceleration path, then it can be used to prove E=mc^2 and finaly E=m*gama*c^2 is derived from both formulas.


I imagined the weights inside moving perpendiculary to the direction of box movement. The relativistic momentum is m*gama(v)*v, so the x component of momentum does not depend only on x component of speed.
 
Last edited:
9
0
Thank you for your thoughts, ppl.

This is true for any derivation.
I believe this is incorrect. I am with George and his explanation. Example: Being a man implies you are a human, but being a human does not imply you are a man.

As far as I know E=mcc can be derived without usin conservation of energy
That is correct. It can be derived in many ways, at least one of those ways uses the LoCE.

Scott
 
A related question: In David Morin's book, he says that we cannot "prove" E = gamma*m*c^2 is conserved, or that p = gamma*m*v is conserved, using ONLY the Lorentz Transformations, only that they are good expressions for the conservation of energy in simple collisions, and they reduce to the Newtonian expressions when velocities are small.

He basically says that experiments have shown that these two are conserved, and then goes on to derive the results of relativistic dynamics from these two results. Of course, if they are conserved in one frame, that they are conserved in another follows from the LTs.

But I am not very confident of this approach, surely the expressions for p and E in relativity can be "proven" only from the LTs, in the general case, since they can be proven in the special (and commonly taught) case of grazing collisions.
 
321
0
A related question: In David Morin's book, he says that we cannot "prove" E = gamma*m*c^2 is conserved, or that p = gamma*m*v is conserved, using ONLY the Lorentz Transformations, only that they are good expressions for the conservation of energy in simple collisions, and they reduce to the Newtonian expressions when velocities are small.

He basically says that experiments have shown that these two are conserved, and then goes on to derive the results of relativistic dynamics from these two results. Of course, if they are conserved in one frame, that they are conserved in another follows from the LTs.

But I am not very confident of this approach, surely the expressions for p and E in relativity can be "proven" only from the LTs, in the general case, since they can be proven in the special (and commonly taught) case of grazing collisions.
You are right, here is a very nice proof based on grazing collisions. I remember that TW "Spacetime Physics" has some similar proofs (maybe not as good).
 
2,945
0
Hello,

First post. Thank you for letting me be a part of the discussion.

My question is, can the Law of Conservation of Energy, http://upload.wikimedia.org/math/2/7/3/273abc16486177bf6cc4c8ec4a4a5fc9.png, be derived using E=MC2.
It depends. The expression E = Mc^2 was derived based on the assumption that energy is conserved. If we simply postulate E = Mc^2 and assume no other quantity is conserved then we cannot derive conservation of energy because (1) energy is that quantity that is conserved, by definition and thus cannot be proved and (2) without conservation of energy another postulate is required such as the conservation of inertial (aka relativistic) mass or the conservation of momentum.

Therefore if we assume that momentum is conserved (simply because M is defined such that momentum is conserved) then yes, it can be derived. Since M is defined such that momentum is conserned then it can be shown that M is also conserved and as such E = Mc^2 is conserved.

Pete
 
3,961
20
You are right, here is a very nice proof based on grazing collisions. I remember that TW "Spacetime Physics" has some similar proofs (maybe not as good).
The proof given in the link posted http://en.wikibooks.org/wiki/Special_Relativity/Dynamics#Derivation_using_the_concept_of_relativistic_mass clearly shows that there is an initial assumption of conservation of energy in the derivation of the momentum equations, so it does not (by itself) prove that energy is conserved in special relativity.

[EDIT] Perhaps it would be more accurate to state their is an assumption of conservation of momentum. When the conservation of momentum is "fixed" so is the conservation of energy.
 
Last edited:
321
0
The proof given in the link posted http://en.wikibooks.org/wiki/Special_Relativity/Dynamics#Derivation_using_the_concept_of_relativistic_mass clearly shows that there is an initial assumption of conservation of energy in the derivation of the momentum equations, so it does not (by itself) prove that energy is conserved in special relativity.
You are looking at the right wiki page, wrong caption. Look here. User "rahuldandekar" was talking about the derivation of momentum conservation based on grazing collisions. There is a similar proof in Taylor-Wheeler "Spacetime Physics".
I do not have an opinion on the energy conservation but I have proven recently to my satisfaction that the energy-momentum 4-vector is conserved for arbitrary systems of particles using only the LT transforms. I am quite sure you remember that thread.
 
Last edited:
321
0
[EDIT] Perhaps it would be more accurate to state their is an assumption of conservation of momentum. When the conservation of momentum is "fixed" so is the conservation of energy.
I don't think so, look at this caption, in the same page.
 
3,961
20
I don't think so, look at this caption, in the same page.
That section uses an assumption of relativistic 3 force and when you look at the section above it for the derivation of relativistic force transformation you see there is an assumption of the relativistic momentum transformation (p=myv).
 
321
0
That section uses an assumption of relativistic 3 force and when you look at the section above it for the derivation of relativistic force transformation you see there is an assumption of the relativistic momentum transformation (p=myv).
You are mixing up the momentum formula ([tex]p=\gamma m v[/tex] ) with momentum "transformation". The wiki page had just established the momentum formula from the grazing collision, from base principles. The wiki article goes on to establish the energy formula from base principles by using the momentum formula that was just established from grazing collisions. So, in this sense, the author has established both momentum and energy relativistic formulas from grazing collisions. No use of LT , exactly as user "raduldandekar" conjectured.
 
3,961
20
You are mixing up the momentum formula ([tex]p=\gamma m v[/tex] ) with momentum "transformation". The wiki page had just established the momentum formula from the grazing collision, from base principles. The wiki article goes on to establish the energy formula from base principles by using the momentum formula that was just established from grazing collisions. So, in this sense, the author has established both momentum and energy relativistic formulas from grazing collisions. No use of LT , exactly as user "raduldandekar" conjectured.

You are right that I used the term transformation incorrectly. In the grazing collision they show that without assuming a change in relativistic mass that classical momentum is not conservered and then change the definition of momentum to ensure that momentum is conserved at relativistic speeds.

Some quotes from the text:

"To preserve the principle of momentum conservation in all inertial reference frames, the definition of momentum has to be changed."

and "This means that, if the principle of relativity is to apply then the mass must change by the amount shown in the equation above for the conservation of momentum law to be true."
 
321
0
You are right that I used the term transformation incorrectly. In the grazing collision they show that without assuming a change in relativistic mass that classical momentum is not conservered and then change the definition of momentum to ensure that momentum is conserved at relativistic speeds.

Some quotes from the text:

"To preserve the principle of momentum conservation in all inertial reference frames, the definition of momentum has to be changed."

and "This means that, if the principle of relativity is to apply then the mass must change by the amount shown in the equation above for the conservation of momentum law to be true."
Correct. This is one of the better wiki pages, the authors put a lot of thought in it.
They show how you can derive the formula for relativistic momentum [tex]p=\gamma mv [/tex] from the momentum conservation in an elastic grazing collision. R.C. Tolman was the first to show it (not as well) , Taylor-Wheeler do it in their book.
Based on the derivation for the momentum formula, the authors do a very nice job of deriving [tex]E=\gamma mc^2[/tex] . This is exactly what user "raduldandenkar" was asking for.
 
9
0
I had thought yesterday that because e=mc2 implies that the speed of light is constant (or perhaps it would be better to say that special relativity states that the speed of light is constant), that that might be enough to prove the LoCE using e=mc2. I was unsure how to prove that.

Today, I was astounded to hear a physicist on CBC Radio (I did not hear his name, but he has a book on a theory of everything), state that if the speed of light is constant then energy must be conserved. He said that was something he learned in while he was obtaining his PHD. He also said that because the laws of physics are true in all frames of reference, that the LoCE must also be true.

I wonder if he meant that mass-energy must be conserved (which is a trivial consequence of e=mc2), but he did actually say the Law of Conservation of Energy is an implication of light being a constant speed.

Interesting.

Scott
 

Related Threads for: Deriving Law of Conservation of Energy from E=MC2

  • Last Post
Replies
6
Views
7K
  • Last Post
Replies
4
Views
38K
  • Last Post
Replies
4
Views
2K
Replies
3
Views
962
  • Last Post
2
Replies
48
Views
6K
  • Last Post
2
Replies
38
Views
39K
  • Last Post
Replies
4
Views
3K
  • Last Post
Replies
4
Views
4K
Top