Deriving moment of inertia from Newton's second law

[danyalasdf]

Homework Statement

We did something very similar to this in lab

http://webenhanced.lbcc.edu/physte/phys2ate/2A LAB HANDOUTS/Moment of Inertia.pdf

Use Newton's Second to derive the expression for the experimentally determined moment of inertia

Homework Equations

Newton's Second Law is F=m*a

s=(1/2)*a*t^2

Experimentally Moment of Inertia

I=r^2(m((gt^2/2s)-t) - mf)

Trying to get to this ^

mf= mass effective not much meaning just mass in kg
If it confusing the gt^2 is divided by 2s then it is subtracted by t and multiplied by r^2 and then minus mf

Torque= F*r= m*r*a

T= (mf + m)(g - a) = tension

The Attempt at a Solution

T= (mf + m)(g - (2*s/t^2))

T= (mf + m)((1/2)(a*t^2) - a)

T= (mf + m)(a((1/2)*t^2 - 1)

I am stuck write here

 

[Pythagorean]

Is calculus is a prerequisite for this course?

 

[danyalasdf]

Is calculus is a prerequisite for this course?

yes it is Physics Calculus Based 2211K

 

[Pythagorean]

Calc may not be necessary.

So what's the physical system you're doing in this problem? Is it the same exact system as in the lab?

 

[danyalasdf]

Calc may not be necessary.

So what's the physical system you're doing in this problem? Is it the same exact system as in the lab?

yes it is the exact same system