- #1
DPMachine
- 26
- 0
Homework Statement
I was looking over my notes and there was a part that didn't make sense.
It's basically using the Euler's formula ([tex]e^{ix}=cos(x)+isin(x)[/tex]) and the fact that [tex]sin(x)=Im(e^{ix})[/tex] to find what Σ sin n sums to.
It starts out like this:
[tex]\sum^{\infty}_{n=1} sin(n) = sin(1) + ... + sin(n)
= Im(e^{i(1)}+ ... +e^{i(n)})
...
[/tex]
But this part isn't relevant to my question... I'll just skip over to the part that confused me:
Here, I don't understand how [tex]Im(e^{i(\frac{n+1}{2})}\frac{sin(n/2)}{sin(1/2)})[/tex][tex]
= Im(e^{i(\frac{n+1}{2})}\frac{sin(n/2)}{sin(1/2)})
= \frac{sin((n+1)/2)sin(n/2))}{sin(1/2)}
[/tex]
turned into [tex]\frac{sin((n+1)/2)sin(n/2)}{sin(1/2)}[/tex]
I understand that [tex]e^{i(\frac{n+1}{2}) = cos((n+1)/2) + isin((n+1)/2)[/tex], by just applying the Euler's formula, but I still can't seem to demystify it. What does the "Im" part do?