Deriving the Differential Equation for Evaporation of a Spherical Water Drop

  • Thread starter Thread starter neelakash
  • Start date Start date
  • Tags Tags
    Drop Water
Click For Summary

Homework Help Overview

The problem involves deriving a differential equation related to the evaporation of a spherical water drop, which is said to evaporate at a rate proportional to its exposed surface area. The original poster seeks to set up the differential equation of motion and determine the time needed for complete evaporation and the velocity at that time.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the evaporation process and the motion of the drop, questioning the context of the problem and the assumptions made regarding forces acting on the drop.

Discussion Status

Some participants have provided guidance on clarifying the context of the problem and the assumptions regarding forces such as gravity and drag. There is an ongoing exploration of the implications of these assumptions on the differential equation and the overall analysis.

Contextual Notes

Participants note the lack of explicit information regarding the direction of motion and the forces acting on the drop, which complicates the formulation of the equation of motion. There are references to potential industrial applications and factors affecting evaporation rates, such as temperature and humidity.

neelakash
Messages
491
Reaction score
1

Homework Statement



A spherical drop of water evaporates at a rate proportional to its exposed surface area as it moves.Set up its differential equation of motion.Find the time needed for complete evaporation.What is the velocity at that time?

Homework Equations





The Attempt at a Solution



The volume of the sphere is :

V=(4/3)πr^3, and the area is A=4πr^2

dV/dt = -k A,the minus sign is to indicate that the volume is decreasing

dV/dt = (4/3)π(3)r^2dr/dt = 4πr^2dr/dt = -k(4πr^2), and simplifing this:

dr/dt = - k

Am I correct upto this?
 
Physics news on Phys.org
Looks a good start.

But the differential equation you wrote describes the evaporation, not the motion -strictly speaking-. You should check what is exactly expected. (context of this exercice)

My usual undestanding is that an equation of motion is based on Newton's law of motion.
Sometimes differential equations are also called equations of motion, kind of abstraction.

Assuming your analysis match the question, then you can easily conclude about the time needed for complete evaporation.

What is the context of this question? Math course, chemical engineering, ... ?
 
That's right I am to find the velocity...stuff that can only be found as we solve the equation of motion invoking Newton's 2nd law.It is found in a mathematical physics question paper.

How to find that F=ma?We are given no force to equate with...Even we do not know in what irection is the drop moving...vertically under gravity or something else?
 
neelakash said:
That's right I am to find the velocity...stuff that can only be found as we solve the equation of motion invoking Newton's 2nd law.It is found in a mathematical physics question paper.

How to find that F=ma?We are given no force to equate with...Even we do not know in what irection is the drop moving...vertically under gravity or something else?

IMO, a good assumption to make would be that the drop is falling under the force of gravity and buoyancy.

If you want a better assumption, you could also include the drag force.
 
I think that would be better to do.
 
Neelakash,

You should find useful information on wiki starting from this page:


If you can assume low (relative) velocities, then the Stokes's drag would be all you need.
Since your droplet would be decreasing in size, the drag force and the mass of the droplet would change in time.

Finally note that this problem has some industrial applications.
In gas conditioning towers, water sprays are often used to cool down a gas stream before further treatment.
The small difference with your problem is that the gas is streaming.
As you may imagine, the efficiency of the cooler tower is essentially determined by the size of the droplets.
If the droplets are not small enough, they will not have enough time to evaporate completely in the tower. When the gases are dusty, this may produce sludges at the bottom of the tower.

Note also that the evaporation rate will depend on the temperature and humidity of the gas. Obviously saturated gas will block any evaporation, and high temperatures will increase evaporation. If you want to know more about this, have a look for "psychrometry" on wiki or elsewhere. The psychrometric ratio will also show you a link between the heat transfer coefficient and the mass transfer coefficient (for a water vapor-air mixture). With all these information, all the details of droplet evaporation in gas stream can be simulated.
 
Last edited:
Is one to compute the velocity of the drops boundary or the speed of the drop as it moves?

Also keep in mind that there are two areas - surface area of the drop, and projected area, which is used in resistance to motion.
 
I am getting a different idea.Should not it be like that:

The drop evaporates and consequently itself energy decreases and that self energy is being converted into kinetic energy?Note that we are only given that dV/dt=-dA/dt and no referene to frictional drags are specified.
 
You must clarify the question.
 
  • #10
I cut the problem and pested it over here and showed my work.That is all.I cannot edit the question.Right?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
3K
Replies
3
Views
7K
Replies
4
Views
4K
Replies
6
Views
10K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
6K
Replies
1
Views
5K
Replies
1
Views
2K