Deriving the Limit of x^3e^(-x^2) as x Approaches Infinity

  • Thread starter Thread starter phillyolly
  • Start date Start date
  • Tags Tags
    Derivative
Click For Summary
SUMMARY

The limit of the function x^3e^(-x^2) as x approaches infinity is 0. This conclusion is reached by applying L'Hôpital's Rule, which simplifies the evaluation of limits involving indeterminate forms. The discussion highlights the importance of recognizing the exponential decay of e^(-x^2) outweighing the polynomial growth of x^3. The final solution confirms that as x increases indefinitely, the product approaches zero.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with L'Hôpital's Rule
  • Knowledge of exponential functions and their properties
  • Basic differentiation techniques
NEXT STEPS
  • Study L'Hôpital's Rule in depth, including its applications and limitations
  • Explore the behavior of exponential functions compared to polynomial functions
  • Practice solving limits involving indeterminate forms
  • Review advanced differentiation techniques for complex functions
USEFUL FOR

Students studying calculus, particularly those focusing on limits and derivatives, as well as educators seeking to enhance their teaching methods in these topics.

phillyolly
Messages
157
Reaction score
0

Homework Statement



lim(x→∞)x^3 e^((-x)^2 )

Homework Equations


The Attempt at a Solution


So I tried taking a derivative as both, multiplication and a fraction. I make a mistake somewhere. I get a very complicated answer.
 
Last edited:
Physics news on Phys.org
OK, I solved it.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
Replies
1
Views
1K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K