Sammyboss
- 3
- 0
Pls does anyone know how to derive for Vout1 and Vout3 in terms of Va and Vb for an inverting operational amplifier. Thank you.
Deriving Vout in an inverting operational amplifier.
- Thread starter Sammyboss
- Start date
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 2K views
Sammyboss
- 3
- 0
Bob S
- 4,662
- 8
See inverting amplifier section in http://physics.usask.ca/~angie/ep316/lab7/theory.htmSammyboss said:
yungman
- 5,741
- 291
There is no Va and Vb! I see two input voltage. I only see Vin1 and Vin2. So you look at Vin1 and Vin2 contribute. Vout1 part due to Vin1 is -(R3/R1)Vin1. Vout1 due to Vin2 is -(R3/R2)Vin2 so the total Vout1:
[tex]V_{out1}=-\left[ \frac{R_3}{R_1}V_{in1}+\frac{R_3}{R_2}V_{in2} \right][/tex]
You try to do the next one.
[tex]V_{out1}=-\left[ \frac{R_3}{R_1}V_{in1}+\frac{R_3}{R_2}V_{in2} \right][/tex]
You try to do the next one.
Sammyboss
- 3
- 0
Thanks a lot. that really helpedyungman said: