Deriving Wave Function for One-Dimensional Sinusoidal Wave

In summary, the highlighted part of the graph does not seem to be derivable from the rest of the text.
  • #1
member 731016
Homework Statement
Please see below and https://openstax.org/books/university-physics-volume-1/pages/16-2-mathematics-of-waves for more details.
Relevant Equations
Please see below
Where did they get the equation in circled in red from? It does not seem that it can be derived from the graph below.
1672944351154.png

Many thanks
 
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  • #2
Figure 16.10 is just a graph of [itex]\sin(theta)[/itex]. It is not referenced in the extract you have posted; why then you would expect the highlighted part to be directly derivable from a figure which is nowhere referred to? Perhaps look at the part of the text where the figure is actually referenced.

I suspect that, prior to the extract you have posted, it is stated that [itex]y[/itex] should have period [itex]\lambda[/itex]. Sine, of course, has a period of [itex]2\pi[/itex], so to get a function with period [itex]\lambda[/itex] you have to use [itex]\sin (2\pi x/\lambda)[/itex], so that [itex]\theta = 2\pi x/\lambda[/itex] is equal to [itex]2\pi[/itex] when [itex]x = \lambda[/itex].
 
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  • #3
pasmith said:
Figure 16.10 is just a graph of [itex]\sin(theta)[/itex]. It is not referenced in the extract you have posted; why then you would expect the highlighted part to be directly derivable from a figure which is nowhere referred to? Perhaps look at the part of the text where the figure is actually referenced.

I suspect that, prior to the extract you have posted, it is stated that [itex]y[/itex] should have period [itex]\lambda[/itex]. Sine, of course, has a period of [itex]2\pi[/itex], so to get a function with period [itex]\lambda[/itex] you have to use [itex]\sin (2\pi x/\lambda)[/itex], so that [itex]\theta = 2\pi x/\lambda[/itex] is equal to [itex]2\pi[/itex] when [itex]x = \lambda[/itex].
Thanks for your reply @pasmith! You meant to say that "it is stated that x should have a period of λ" instead of "
1672949737419.png
" correct?

I guess they took an arbitrary point along the wave to for ratio of phase to wavelength which they also could of picked a point on the wave which has a π phase which has a wavelength λ/2.
1672950703818.png

Many thanks
 
  • #4
Callumnc1 said:
You meant to say that "it is stated that x should have a period of λ" instead of "
1672949737419-png.png
" correct?
incorrect. In ##y=\sin(2\pi x/\lambda)##, it is the value of y that repeats as x increases by λ, so we say y has period λ.
 
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  • #5
haruspex said:
incorrect. In ##y=\sin(2\pi x/\lambda)##, it is the value of y that repeats as x increases by λ, so we say y has period λ.
Thank you @haruspex !
 

FAQ: Deriving Wave Function for One-Dimensional Sinusoidal Wave

What is a one-dimensional sinusoidal wave?

A one-dimensional sinusoidal wave is a wave that oscillates in a single spatial dimension and can be mathematically represented by a sine or cosine function. It is characterized by its wavelength, amplitude, and frequency, and its general form is given by y(x,t) = A * sin(kx - ωt + φ), where A is the amplitude, k is the wave number, ω is the angular frequency, and φ is the phase constant.

How do you derive the wave function for a one-dimensional sinusoidal wave?

To derive the wave function for a one-dimensional sinusoidal wave, start with the general form of the wave equation: y(x,t) = A * sin(kx - ωt + φ). Here, A is the amplitude, k is the wave number (2π/λ, where λ is the wavelength), ω is the angular frequency (2πf, where f is the frequency), and φ is the phase constant. This equation describes the displacement y at position x and time t.

What is the relationship between wave number and wavelength?

The wave number k is inversely related to the wavelength λ. Specifically, k is defined as k = 2π/λ. This relationship indicates that as the wavelength increases, the wave number decreases, and vice versa. The wave number represents the number of wavelengths per unit distance.

What is the significance of the phase constant in the wave function?

The phase constant φ in the wave function y(x,t) = A * sin(kx - ωt + φ) determines the initial phase of the wave at t = 0 and x = 0. It shifts the wave horizontally along the x-axis. Different values of φ result in different starting points of the wave, but do not affect the wave's amplitude, wavelength, or frequency.

How do amplitude and frequency affect the wave function?

The amplitude A affects the maximum displacement of the wave from its equilibrium position; higher amplitude means greater displacement. The frequency f, related to the angular frequency ω by ω = 2πf, determines how many oscillations occur per unit time. Higher frequency means more oscillations per second. Both amplitude and frequency are crucial in defining the characteristics and energy of the wave.

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