Describe geometrically the level surfaces of the functions

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SUMMARY

The discussion focuses on the geometric description of level surfaces for the function f(x, y, z) = (x² + y² + z²)^(1/2). A level surface is defined as the set of points (x, y, z) where f(x, y, z) equals a constant C. By squaring both sides of the equation, the level surface can be expressed as x² + y² + z² = C², which represents a sphere centered at the origin with radius C.

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matt_crouch
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So the question is as titled

i) f=(x^2 +y^2 +z^2) ^1/2

if I can figure out the method I can solve the other equations but I'm not really sure where to start I know that a function f(x,y,z) of a level surface well be constant so do I just find del f ?
 
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matt_crouch said:
So the question is as titled

i) f=(x^2 +y^2 +z^2) ^1/2

if I can figure out the method I can solve the other equations but I'm not really sure where to start I know that a function f(x,y,z) of a level surface well be constant so do I just find del f ?
No, this has nothing to do with the gradient. A "level surface" for any function f(x,y,z) is, as you say, the set of points (x, y, z) where f(x, y, z)= C, a constant.

Here, that gives (x^2+ y^2+ z^2)^{1/2}= C. What do you get if you square both sides?
 
so you just square both sides so id get

x2+y2+z2= C2

where C2 is just another constant

is that right?
 

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