Design a 15 dB π Attenuator with 600Ω Impedance

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SUMMARY

The discussion focuses on designing a π section symmetrical attenuator that achieves a voltage attenuation of 15 dB with a characteristic impedance of 600 Ω. The calculations reveal that Z1 should be set to 718 Ω and Z3 to 3320 Ω to meet the specified requirements. The voltage ratio Vin/Vout is calculated using the formula (Z1 + Z3) / Z1, and the attenuation is confirmed to be 15 dB. Corrections were made regarding the identification of components in the circuit, ensuring accurate representation of the input and output voltages.

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Homework Statement


Design a π section symmetrical attenuator to provide a voltage attenuation of 15 dB and a characteristic impedance of 600 Ω.

image.jpg


Zc=600Ω,[itex]\alpha[/itex]=15dB (attenuation)
Z1,Z3=?

Homework Equations

The Attempt at a Solution



[itex]\alpha[/itex][dB]=20log(Vin/Vout)=15
[itex]\alpha[/itex]=5.623

Vin/Vout=(Z1+Z2)/Z1

Zc=√ZocZsc
Zoc=(Z1(Z1+Z3))/(2Z1+Z3)
Zsc=(Z1Z3)/(Z1+Z3)

Zc=Z1√1-2/(2+Z3/Z1)

Z1D=600

Z3/Z1=4.623
D=0.835

Z1=718Ω
Z3=3320Ω
 
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I'd be inclined to show the arrows for Vin and Vout upside down to how you have, though I guess it makes no difference.

Vin/Vout=(Z1+Z2)/Z1 should be Z3 not Z2

Your figures give -15 dB, and 609.6 ohms for Zin
 
I have made a typing error,it is Z3
 

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