- #1

narbij

- 7

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the diameter of the vertical tube is 22mm which is constant. the inclined tube has 3 sperate tubes of a 8mm diameter each, therefore the diameter of the inclined tube can be altered.

i have these formulas:

change in pressure = specific gravity of liquid in manometer times L(the column length) times the sin of the angle.

So far i know from theory, if you apply a certain amount of pressure, the fluid would displace a certain amount. Now in the vertical tube, the displacement change in h and in the inclined tube, it would be change in l. The volume of the amount that has been displaced is constant.. So i have made an equation which states that:

change in h * cross-sectional area in the vertical tube of the displaced h= change in l*cross-sectional area in the inclined tube of the displaced l .

Any help would be much appreciated as I am extremely extremely extremely extremely extremely stuck