Designing a Ballistic Spring System for Measuring Bullet Speed

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SUMMARY

The discussion focuses on designing a ballistic spring system to measure bullet speed, specifically deriving the bullet's speed (VB) in terms of mass (m), block mass (M), spring constant (k), and maximum compression (d). The key equations utilized include conservation of momentum (Pi = Pf) and energy conservation principles (Ki + Ui = Kf + Uf). The final expression for bullet speed is derived as VB = √((m + M)kd²/m²), confirming the solution aligns with the textbook answer.

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  • Understanding of conservation of momentum principles
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  • Knowledge of spring mechanics and Hooke's Law
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Homework Statement


You have been ask to design a "ballistic spring system" to measure the speed of bullets. A bullet has a mass of m is fired into a block with mass M. The block, with the embedded bullet, then slides across a frictionless table and collides with a horizontal spring whose spring constant is k. The opposite end of the spring is anchored to a wall. The spring's maximum compression is d is measured.

A. Find a expression for the bullet's speed VB in terms of m, M, k, d.
B. Not help is needed
C. " "


Homework Equations


I think,
Pi = Pf
Ki + Ui = Kf + Uf


The Attempt at a Solution



mVB + MV0 = (m + M)V1

MV0 goes to 0

Equation 1. VB = (m + M)V1
......m
________________________
.5(m + M)V1^2 + (m + M)gy1 = .5(m + M)V2^2 + (m + M)gy2 + .5kd^2

Having the Y axis start at the bullets height - (m + M)gy1, (m + M)gy2 go to 0

.5(m + M)V2^2 I think goes to 0

Equation 2. V1 = Sq. Rt.(kd^2/(m + M))

Plug 1 into 2

VB = Sq. Rt. ((m + M)^2kd^2/ m^3 + Mm^2)


I don't know. I tried so many things... just not getting it...
 
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Wow, just realize if i would have factor better:
VB = Sq. Rt. ((m + M)^2kd^2/ m^3 + Mm^2)

Becomes VB = Sq. Rt.((m + M)kd^2/m^2)

Which is the answer the book had.
 

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