# Determinant formula with einstein notation proof

1. Sep 4, 2010

### Mugged

Hello, Im supposed to prove that the determinant of a second order tensor (a matrix) is equal to the following:

det[A] = $$\frac{1}{6} \epsilon_{ijk} \epsilon_{pqr} A_{pi} A_{qj} A_{rk}$$

$$A_{11}(A_{23}A_{32}-A_{22}A_{33}) + A_{12}(A_{21}A_{33}-A_{23}A_{31}) + A_{13}(A_{22}A_{31}-A_{21}A_{32})$$