 #1
 147
 0
Hi all,
This is a beginning step in proving aXb=absin(theta)
thank you
This is a beginning step in proving aXb=absin(theta)
thank you
Attachments

4 KB Views: 946
Assuming that expression with a's is the determinant, then yes: it must be the whole thing squared.Hi all,
This is a beginning step in proving aXb=absin(theta)
thank you