- #1

- 538

- 148

[tex] \frac{d}{dt} \det{A(t)} = \lim_{\epsilon \to 0} \frac{\det{(A+\epsilon \frac{dA}{dt})} - \det{A}}{\epsilon} [/tex]

which produces the right answer, so I believe that it may be correct. This looks very much like a Taylor expansion, but I'm having trouble justifying it exactly - does anyone know the proper way to Taylor expand a determinant, and if the above expression is actually true?