Determine Force for inclining platform

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The discussion centers on calculating the force required for an inclined platform with a load of 12,000 kg. Participants clarify that the load is not accelerating and that the cylinder geometry affects the calculated force. A specific moment calculation yields a load of 18,888 kg, equating to 185,100 newtons. Concerns arise about the safety of the setup, questioning whether the load is real or a mockup. The thread ultimately gets closed due to concerns over discussing potentially dangerous scenarios.
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A hydraulic actuator force, F is 3000m from the right is lifting the platform upwards. The load 12000kg is UDL. How do I calculate for F?
inclined_beam.jpg
 
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Is it accelerating the load? ##F## will also be a function of the cylinder geometry.
 
No it's not accelerating the load. The cylinder geometry will be depending on the calculated force.
 
Moment: 12,000 kg at 3.000 m = 36,000 kg⋅m .
If one lift cylinder is located at 1.906 m from the fulcrum,
the load will be; 36,000 / 1.906 = 18,888. kg .
18,888 kg * 9.8 = 185,100 newton.
Have you included the mass of the tilting platform?
 
jr5 said:
The load 12000kg is UDL. How do I calculate for F?
The load is 12,000 kg, and you are asking for advice on an Internet forum? Can you provide a link to your buisiness insurance company please?
 
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berkeman said:
The load is 12,000 kg, and you are asking for advice on an Internet forum? Can you provide a link to your buisiness insurance company please?
It's not for company, it's a mockup.
 
jr5 said:
It's not for company, it's a mockup.
I don't understand. Is the load really 12,000 kg, or is that mocked up too? If it's real, what happens if/when the support fails?
 
berkeman said:
I don't understand. Is the load really 12,000 kg, or is that mocked up too? If it's real, what happens if/when the support fails?
Jeopardy.
 
DeBangis21 said:
Jeopardy.
You are not helping your case to keep this thread open; thread is now closed per the "no dangerous discussions" clause in the PF Rules (see INFO at the top of the page).
 

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