- #1
jr5
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- TL;DR
- A hydraulic actuator force, F is 3000m from the right is lifting the platform upwards. The load 12000kg is UDL. How do I calculate for F?
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SUMMARY
The discussion focuses on calculating the force required for an inclining platform with a load of 12,000 kg. The calculated moment is 36,000 kg⋅m, and the load at a distance of 1.906 m from the fulcrum results in a force of 185,100 newtons. Participants express concerns about the safety and implications of using such a load, questioning whether it is a real scenario or a mockup. The thread was ultimately closed due to safety concerns regarding dangerous discussions.
PREREQUISITES- Understanding of basic physics principles, particularly torque and force calculations.
- Familiarity with load distribution concepts, specifically Uniformly Distributed Load (UDL).
- Knowledge of safety regulations and risk assessment in engineering contexts.
- Experience with mechanical systems involving inclining platforms and their dynamics.
- Research "Torque calculations in mechanical systems" to deepen understanding of force distribution.
- Study "Uniformly Distributed Load (UDL) in structural engineering" for better load management techniques.
- Explore "Safety protocols for heavy load handling" to ensure compliance with safety standards.
- Investigate "Mechanical advantage in lever systems" to optimize design for inclining platforms.
Engineers, safety inspectors, and anyone involved in the design or analysis of mechanical systems that handle heavy loads, particularly those working with inclining platforms.
- #2
erobz
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Is it accelerating the load? ##F## will also be a function of the cylinder geometry.
- #3
jr5
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No it's not accelerating the load. The cylinder geometry will be depending on the calculated force.
- #4
Baluncore
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Moment: 12,000 kg at 3.000 m = 36,000 kg⋅m .
If one lift cylinder is located at 1.906 m from the fulcrum,
the load will be; 36,000 / 1.906 = 18,888. kg .
18,888 kg * 9.8 = 185,100 newton.
Have you included the mass of the tilting platform?
If one lift cylinder is located at 1.906 m from the fulcrum,
the load will be; 36,000 / 1.906 = 18,888. kg .
18,888 kg * 9.8 = 185,100 newton.
Have you included the mass of the tilting platform?
- #5
berkeman
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The load is 12,000 kg, and you are asking for advice on an Internet forum? Can you provide a link to your buisiness insurance company please?jr5 said:
- #6
jr5
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It's not for company, it's a mockup.berkeman said:
- #7
berkeman
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I don't understand. Is the load really 12,000 kg, or is that mocked up too? If it's real, what happens if/when the support fails?jr5 said:
- #8
DeBangis21
Gold Member
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Jeopardy.berkeman said:
- #9
berkeman
Admin
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You are not helping your case to keep this thread open; thread is now closed per the "no dangerous discussions" clause in the PF Rules (see INFO at the top of the page).DeBangis21 said:
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