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Determine if the improper integral is divergent or not

  • #1
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12

Homework Statement


Determine if the improper integral is divergent or convergent .
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Homework Equations


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The Attempt at a Solution


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When i solved the first term using online calculator , the answer was "The integral is divergent" . However , I got 0 .
Where is my mistake ?
 

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Answers and Replies

  • #2
Orodruin
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You cannot generally do things like ##\infty - \infty = 0##. Furthermore, what you have is not ##\infty - \infty## as ##1/[2(0^2 - 1)] = -1/2##.
 
  • #3
288
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You cannot generally do things like ##\infty - \infty = 0##. Furthermore, what you have is not ##\infty - \infty## as ##1/[2(0^2 - 1)] = -1/2##.
It should be ##-1/[2(1^2-1)] +- 1/[2(0^2-1)]= -1/0 + 1/2 = -\infty+1/2##
So , it's divergent . Right ?
 

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