Determine if the sum Converges or Diverges

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Homework Statement



Three series problems: 1. Difference of the infinite sum from n=1 to infinity of 1/(2n-1)^3 minus the sum from n=1 to 100 of the same term, with a question about the size of that difference; 2. Sum from n=1 to infinity of (1 + 1/n)^n; 3. Sum from n=1 to infinity of (-1)^n (5n-1)/(n+5).


The Attempt at a Solution



1. I have no idea. I know that the summation of the series converges.


2. I think it would diverge because the limit of the function does not equal zero.


3. I have tried the ratio test and got 1. Can't use the alternating series test because when ignoring signs the function increases.
 
For 3 what's the limit of (5n-1)/(n+5) and what does that tell you about convergence? For 1 I think they might be asking you to estimate the difference using an integral.
 
2) is correct
3) Think about the function [itex]f(x)=\ln x[/itex]
 
Last edited:
Dick said:
For 3 what's the limit of (5n-1)/(n+5) and what does that tell you about convergence? For 1 I think they might be asking you to estimate the difference using an integral.

The limit of (5n-1)/(n+5) as x approaches infinity equals 5 thus meaning that the series in divergent? I think
 
hunt_mat said:
2) is correct
3) Think about the function [itex]f(x)=\ln x[/itex]
[itex][/QUOTE]<br /> <br /> I'm not sure what [itex]f(x)=\ln x[/quote] means. Can you plus explain.[/itex][/itex]
 
McAfee said:
The limit of (5n-1)/(n+5) as x approaches infinity equals 5 thus meaning that the series in divergent? I think

Right. If the nth term of a series doesn't approach 0 then it's always divergent. Now can you write an integral that's greater than the difference in 1?