Determine its speed after it has slid a distance of 3.00m down the ramp.

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Homework Help Overview

The problem involves a 2.00kg mass sliding down a frictionless inclined plane at a 30-degree angle, with the goal of determining its speed after sliding 3.00m. The context includes concepts from energy conservation and kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of conservation of energy and work-energy principles. There is an attempt to calculate height using trigonometric functions, and questions arise regarding the accuracy of these calculations.

Discussion Status

Some participants have offered alternative approaches to the problem, including the work-energy theorem. There is recognition of a potential miscalculation in determining height, prompting further exploration of the setup and assumptions.

Contextual Notes

Participants note the importance of correctly applying trigonometric functions to find height and the implications of using different energy principles. The original poster expresses confusion regarding the expected answer, indicating a need for clarification on their calculations.

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Homework Statement


A 2.00kg mass starts from rest and slides down a frictionless inclined plane that makes an angle of 30 degrees with the horizontal. Determine its speed after it has slid a distance of 3.00m down the ramp.

Homework Equations


I am leaning about Laws of Conservation of Energy
∑Ek=∑Ep
Ek=(1/2)mv2
Ep=mgh
maybe SOH CAH TOA to get the height

The Attempt at a Solution


using a height of 2.5980, from 3cos(30), i put that into my equation but got 7.1396 m/s
when i know the answer is 5.4 m/s?¿¿
 
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Hey!

You said that you're learning about conservation on Energy,
Then i think it could be usefull the theorem of work and kinect energy.
It simply said that the sum of works that acts on a particle is equal to the change in kinect energy.
When you dou a free body diagram you realize that the only force doing work is the horizontal component of weight,( because the normal force is perpendicular to displacement then work is 0) then you know

mgsin30*3(displacement)=1/2mv^2
you solve for v, and you get 5,4 m/s

Tell me if you already learn the theorem, if your not, there's another way to solve the problem.
 
goracheski said:

Homework Statement


A 2.00kg mass starts from rest and slides down a frictionless inclined plane that makes an angle of 30 degrees with the horizontal. Determine its speed after it has slid a distance of 3.00m down the ramp.

Homework Equations


I am leaning about Laws of Conservation of Energy
∑Ek=∑Ep
Ek=(1/2)mv2
Ep=mgh
maybe SOH CAH TOA to get the height

The Attempt at a Solution


using a height of 2.5980, from 3cos(30), i put that into my equation but got 7.1396 m/s
when i know the answer is 5.4 m/s?¿¿
You've got the right idea, but take a closer look at how you determined the value for h.
 
Thank you gneill I realized I used CAH instead of SOH :S
 

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