Determine Limit of Factorial Sequence a_n

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SUMMARY

The sequence defined by an = (n!)/(2n! + 1) converges to 0 as n approaches infinity. The reasoning involves comparing the growth rates of the numerator and denominator, where both factorials grow similarly, leading to the conclusion that the limit exists. By applying the squeeze theorem, if 0 ≤ an ≤ bn for a suitable bn that converges, then an must also converge. This formal approach confirms the intuitive expectation of convergence.

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  • Familiarity with limits and convergence concepts
  • Knowledge of the squeeze theorem in calculus
  • Basic algebraic manipulation of inequalities
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Homework Statement


Determine the divergence or the convergence of the sequence. If it converges find its limit.

a_{n} = (\frac{(n)!}{2n!+1})


The Attempt at a Solution



All I know about factorials is for example 4! = 1*2*3*4. So as far as limits go I'm clueless. please help!
 
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I like to think of limits this way. First intuatively say why it should converge or diverge, then apply the intuation in a rigorous way. In this case both top and bottom are about the same thing so you would expect it to converge. How to say this in a formal manner? Use an inequality that will enable you to cancel the factorials and use the theorem that says if 0 \leq a_n \leq b_n for each n, then if b_n converges, so does a_n.
 

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