It may be assumed that the human body can withstand an acceleration of 3g's without sustaining serious injury. A person is driving a car at 60 miles per hour. Determine the shortest distance such that the car could be brought to a stop (at constant acceleration) without the driver sustaining serious injury.
Ag's = a/g
d = (Vi + Vf)/2 * t (d stands for displacement)
The Attempt at a Solution
I converted the 3g's into an acceleration so I at least have a comparable number when I try and get the answer. 3*32ft/s2 = 96ft/s2
I haven't done this type of problem in quite a few months, so I forget where to start per say. I did convert the 60 miles per hour to feet per second, 88ft/s. I don't remember if the equation I listed above is the right one to use in this situation, especially since I don't know time or the displacement.