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## Homework Statement

Determine the difference in potential between A and B.

## Homework Equations

Kirchhoff's rules for current (loop, junction), V = IR

## The Attempt at a Solution

I have found the currents through the resistors:

12 - 3.9a - 1.2b - 9.8a = 0 (loop rule)

12 - 3.9a - 6.7c - 9 - 9.8a = 0 (loop rule)

a = b + c (junction rule)

c = -1.0295 & b = 1.75196 & a = 0.722456

6.7 ohm resistor has 1.02 A counterclockwise

3.9 ohm and 9.8 ohm resistors have 0.72 A clockwise

1.2 ohm resistor has 1.7 A clockwise.

What do I do from here? I know that if A and B were in series, the difference in potential between them would be a drop which equals the potential differences across each component between them in series, but this is in parallel, and so I don't know what to do.