Determine the distance of the center of gravity from the end X of the plank?

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SUMMARY

The discussion focuses on calculating the distance of the center of gravity from the end X of a non-uniform plank that is 2.50m long and weighs 950N. The readings from force-meters A and B, positioned 0.40m from each end, are 570N and 380N respectively. Using the principle of moments, the equilibrium condition is established where the sum of moments around a point equals zero, leading to the determination of the center of gravity's position.

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  • Understanding of static equilibrium principles
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  • Familiarity with force measurements using spring balances
  • Basic concepts of center of gravity in physics
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Homework Statement


A non-uniform plank of wood XY is 2.50m long and weighs 950N. Force-meters (spring balances) A and B are attached to the plank at a distance of 0.40m from each end, as illustrated in the Figure below

http://img266.imageshack.us/img266/2377/physicsp23bgh5.png​
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When the plank is horizontal, force-meter A records 570N

(i) Calculate the reading on force-meter B
(ii) Determine the distance of the center of gravity from the end X of the plank.

Homework Equations


Moment = Force x Perpendicular Distance

The Attempt at a Solution


(i) A + B = 950N
B = 950 - 570 = 380N

(ii) I don't know how to solve this question, need help! :frown:
 
Last edited by a moderator:
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In equilibrium, all the moments (A, B, gravity) cancel out.
 

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