 #1
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 10
Δ1. Homework Statement
Below
[/B]Potential energy = kinetic energy
MgΔY=1/2 mΔv^2
Vf^2=Vi^2+2gx1
For question 49, I used the first equation, and the result is Δv^2=2gY. Then, solving for x1 in the second equation, I got x1=Δv^2 / 2g. Substituting ΔV^2 in x1 results in x1=Y. Answer is A. I am not sure if I should have used H instead of Y, though. But then I would use D, too. I need clarifications, please.
50) since, the masses cancel, the horizontal distance would be the same for M and 2M. Answer C.
51) not sure of it, but friction always slows the motion. So, I guess it is A.
Am I right?
Below
Homework Equations
[/B]Potential energy = kinetic energy
MgΔY=1/2 mΔv^2
Vf^2=Vi^2+2gx1
The Attempt at a Solution
For question 49, I used the first equation, and the result is Δv^2=2gY. Then, solving for x1 in the second equation, I got x1=Δv^2 / 2g. Substituting ΔV^2 in x1 results in x1=Y. Answer is A. I am not sure if I should have used H instead of Y, though. But then I would use D, too. I need clarifications, please.
50) since, the masses cancel, the horizontal distance would be the same for M and 2M. Answer C.
51) not sure of it, but friction always slows the motion. So, I guess it is A.
Am I right?
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