Determine the electron's velocity.

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SUMMARY

The discussion focuses on calculating the velocity of an electron subjected to a magnetic field. The force experienced by the electron is given as F = (3.4i - 1.9j)x10^-13 N, and the magnetic field is B = (0.50 T)k. Using the equation v = F/qB, where the charge of the electron is q = 1.6x10^-19 C, the correct velocity components were determined to be v(x) = -2.4x10^6 m/s and v(y) = -4.3x10^6 m/s after resolving the vector equation F = q(v × B).

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Homework Statement


An electron experiences a force F = (3.4i - 1.9j)x10^-13 N when passing through a magnetic field B = (0.50 T)k Determine the electron's velocity.
v(x) =
v(y) =

Homework Equations


v = F/qB


The Attempt at a Solution


v = (3.4i - 1.9j)x10^-13 / (1.6x10^-19)(0.50)k = (4.25i - 2.375j)x10^6
v(x) = 4.25x10^6
v(y) = -2.375x10^6

I know I'm doing something wrong, I'm just not sure what. Please help.
 
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Consider that you're dealing with a vector equation. F = q(v \times B)

Your magnetic field vector, B, has only a single component (the k component), so the cross product with the velocity vector will be pretty simple. If you assume that the velocity vector has components vi, vj, vk, what is the cross product?

Multiply the cross product components by the charge and equate the corresponding force components.
 
thanks, I was able to figure it out.

v(x) = -2.4x10^6 m/s
v(y) = -4.3x10^6 m/s
 

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