1. The problem statement, all variables and given/known data A force P acts as shown on 200kg block placed on a inclined plane . The static coefficient between the block and the plane is 0.5 . Determine the force P to ensure the block is in the verge of moving down. 2. Relevant equations 3. The attempt at a solution Wsin10 +P cos 20 = Fs P cos 20 = 0.5( P sin20 - W cos 10 ) -Wsin 10 P cos 20 = 0.5( P sin20 - (200x9.81) cos 10 ) -(200x9.81)sin 10 0.17P = 0.5( 0.34P - 1932) - 340.7 0.94P = 0.17P - 966- 340.7 0.17P - 0.94P = 1306.7N P =-1697N , but the ans given is P = 560N , which part of my working is wrong ?