An 18-g rifle bullet traveling 200 m/s buries itself in a 3.6-kg pendulum hanging on a 2.8-m-long string, which makes the pendulum swing upward in an arc. Determine the horizontal component of the pendulum's displacement. What I tried was find the momentum of the bullet, then find the velocity of the pendulum when it hits. Pbefore= (0.018kg)(200) Pbefore=Pafter 3.6 Kg*m/s = (3.6kg+0.018kg)v` vf=0.995m/s vi= 0m/s d(y)=2.8 d(x)= ? -y=1/2a(t^2)+vi(t) -2.8= 1/2(-9.8)(t^2) t^2=0.571 root "t" = root "0.571" t= 0.576 x=vt x=0.995*0.576 x= 0.573m the answer looks wrong... i think.