Determine the Moment and the Maginitude of the Moment

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SUMMARY

The discussion focuses on calculating the moment of a weight (86 lb) about a point O on a horizontal table top, with the center of gravity located at point G. The initial calculations for moments about the x and y axes were incorrect due to unit confusion, as the distances were initially measured in inches instead of feet. After converting the distances to feet, the correct moments were determined: Mx = -372.6638 lb-ft and My = 157.66638 lb-ft. The resultant moment Mo was calculated as 404.644 lb-ft.

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Homework Statement


The weight of the printer is 86 lb with center of gravity at point G. Determine the moment MOof this weight about point O on the horizontal table top. Find the magnitude of MO.


Homework Equations





The Attempt at a Solution


My initial impression was to find the moments about the x, y and z axes and that these would give me their i, j and k components respectively

Mx = (86 lb)(52")
= 4472 lb-ft
My = (86lb)(22")
= 1892 lb-ft

But I've compared these values to an identical question, with altered numbers, in my textbook and my values are much too large to be be the i and j components respectively (there is no k component because the force is parallel to the z axis). So what am I missing?
 

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Just found my mistake. I confused my units; the units given in the diagram are in inches, whereas the system and the example question want and give their answers respectively in feet. I converted the measurements in the diagram to feet and my answer is as follows:

Mx = -(86 lb)(4.33 ft)
= -372.6638 lb-ft

My = (86 lb)(1.833ft)
= 157.66638 lb-ft

Mo = sqrt(372.6638^2 + 157.6638^2)
Mo = 404.644 lb-ft

These answers are correct.
 
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