Determine the nth order Maclaurin polynomial

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SUMMARY

The nth order Maclaurin polynomial for the function 1/(1-x)² can be derived using the known Maclaurin series expansion. The series for 1/(1-x) is expressed as 1 + x + x² + x³ + ... + xⁿ + O(xⁿ⁺¹). To find the nth order polynomial for 1/(1-x)², one can utilize the Taylor series expansion formula, which simplifies the process of determining the coefficients aₙ. The correct approach involves grouping the same powers of x to form the polynomial.

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Homework Statement


Determine the nth order Maclaurin polynomial for 1/(1-x)2


Homework Equations



The known Maclaurin polynomial series: 1/(1-x)= 1+x+x2+x3+...+xn +O(xn+1)

The Attempt at a Solution



I tried expanding the bottom to get 1/ (1-2x+x2)) then wrote it in the form to match and got 1/(1-(2x-x2) I then proceded to expand..and got 1+ (2x-x2) + (2x-x2)2...+xn +O(xn+1) can anyone tell me if I got it right? Or am I suppose to be doing something else?
 
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Seems reasonable. All you need to do is to write it out as a Maclaurin series, that is to group the same powers of x together in a form a_n x^n

Alternatively, using the general Taylor series expansion formula you will have easier time finding the constants an.
 

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