Determine the polarizability of a wire segment.

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SUMMARY

The discussion focuses on determining the polarizability of a short, thin copper wire segment with a length of 0.0105 m, influenced by a negatively charged spherical metal ball with charge -Q. The relevant equations include the electric field E = k*2qL/r^3 and the dipole field E(dipole) = k*2*alpha*E(sphere)/r^3. Participants express frustration over the complexity of the variables involved and seek guidance on how to derive values from these equations.

PREREQUISITES
  • Understanding of electrostatics, specifically charge distribution and induced charges.
  • Familiarity with the concept of polarizability in materials.
  • Knowledge of basic physics equations related to electric fields and forces.
  • Proficiency in manipulating algebraic equations to solve for unknowns.
NEXT STEPS
  • Study the concept of electric fields generated by point charges and their effects on nearby conductors.
  • Learn about the derivation and application of polarizability in conductive materials.
  • Explore the relationship between induced charge and external electric fields in conductive wires.
  • Investigate the use of computational tools for simulating electrostatic interactions in complex systems.
USEFUL FOR

Students in physics courses, particularly those studying electrostatics, as well as educators and researchers interested in the behavior of conductive materials in electric fields.

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Homework Statement



The center of the spherical metal ball of
radius R, carrying a negative charge -Q, is
located a distance r from the center of a short,
thin, neutral copper wire of length L. The
induced charges at the two ends of the wire is
±q. Determine the polarizability of the wire
segment which has a length L = 0.0105 m.

Homework Equations



E = k*2qL/r^3
F = qE
E(dipole) = k*2*alpha*E(sphere)/r^3

The Attempt at a Solution



I am given so many variables that I could not find a way to get any values from these equations.
 
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Bump, this question is driving me crazy, I would love some input.
 

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