Determine the resultant internal loadings in the crane

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SUMMARY

The discussion centers on calculating the resultant internal loadings in a jib crane, specifically at cross sections A, B, and C. The boom DF and column DE each have a uniform weight of 50 lb/ft, and the hoist and load together weigh 300 lb. The correct calculation for the force acting on beam DF was determined to be 650 lb, derived from multiplying the weight per foot by the length of the beam. Additionally, the downward force at point D was confirmed to be 250 lb, calculated from the 5 feet of column above cross-section C.

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jjiimmyy101
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QUESTION: The boom DF of the jib crane and the column DE have a uniform weight of 50 lb/ft. If the hoist and load weight 300 lb, determine the resultant internal loadings in the crane on cross sections through points A, B, and C. (Diagram and answers are attached)

I'm just hoping someone could look at what I did and tell me if I did it correctly.
 

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Here's point C
 

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Looks good to me, but did you take the correct weight for DC in your calculation of point C?
 
The boom DF of the jib crane and the column DE have a uniform weight of 50 lb/ft.

What I did was find the force acting on the entire beam DF, not just DC.
That's why I got 650 lb (50lb/ft*13ft and it acts @ 6.5ft). Is that the right way to do it? And I was wondering if that force I put right on point D is correct. Thanks for the input.
 


Wouldn't the downward force placed at D be 250 lb?

There is 5 feet of column above cross-section C. So wouldn't you multiply (5 ft)*(50 lb/ft) = 250 lb?
 

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