1. The problem statement, all variables and given/known data A crane lifts its 500N load to the top of the building from A to B. Distances are shown on the diagram. Calculate how much work is done by the crane Known variables: AB= displacement= 50m AC=horizontal distance=30m BC=vertical distance=40m 2. Relevant equations Work done= force * distance covered in direction of force W=F.S Force=mass* acceleration F=ma Hypotenuse= Root ( Adjacent^2 + Opposite^2 ) 3. The attempt at a solution From the diagram it can be seen that there the DISPLACEMENT is AB or 50 M. The load is 500N which will require a force in upward direction of 500N. I am confused with which variables to use but nevertheless Work done in upward direction(BC): W=FS =500N*40M=20000NM Work done in horizontal direction(AC): W=FS =500N*30M=15000NM I'm unsure about this one if 500N force will be required because we are not pushing a body on the ground and not countering a friction of 500N Work done in AB? W=FS =500N * 50M =25000NM (This can't be right can it? Because from what I think the crane will first lift the weight up and then rotate) This is a simple highschool question and I might be overcomplicating it but I am really confused which variables to use since the question should have ONE answer.