Determine the resultant of the coplanar forces

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Discussion Overview

The discussion revolves around determining the resultant of coplanar forces, focusing on the calculations of both the magnitude and angle of the resultant vector. Participants are sharing their approaches and results, including mathematical reasoning and suggestions for visual aids.

Discussion Character

  • Mathematical reasoning, Technical explanation, Homework-related

Main Points Raised

  • One participant calculates the components of the resultant forces as Rx = 100 and Ry = 200, leading to an angle O(theta) of 64 degrees.
  • Another participant reports an angle of approximately 63 degrees and inquires about the magnitude of the resultant.
  • A third participant provides a magnitude calculation of R = √(100^2 + 200^2) = 223.62.
  • One participant confirms the method used for calculating the resultant and suggests rounding the result of R = √{100^2 + 200^2} = √{50000} to the appropriate answer.

Areas of Agreement / Disagreement

There is no consensus on the angle of the resultant, with participants reporting slightly different values (64 degrees vs. approximately 63 degrees). The magnitude calculation appears to be agreed upon, but the rounding and final value are not explicitly settled.

Contextual Notes

Participants mention the importance of sketches for clarity, indicating that visual representation may aid in understanding the problem, though no sketches are provided in the discussion.

Who May Find This Useful

This discussion may be useful for students or individuals working on problems related to vector addition and resultant forces in physics or engineering contexts.

tremain74
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Homework Statement
I have a problem that states to Determine the resultant of the coplanar forces 100 N at 0 degrees and 200 N at 90 degrees. The answer is 224 N, Ox(the O is theta) = 64 degrees
Relevant Equations
I used the resultant formulas Rx = 100cos(0) + 200cos(90) . Ry = 100sin(0) + 200sin(90). TanO = Ry/Rx.
I used Rx = 100cos(0) + 200cos(90) = 100. Ry = 100sin(0) + 200sin(90) = 200. tanO = Ry/Rx = 2. Therefore O(theta) = inv tan (2) = 64 degrees.
 
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I get the angle as 63.<something> degrees. What do you get for the magnitude of the resultant?

BTW, it's best to do a sketch of this kind of problem to help in your thinking (and our checking). You can upload a sketch using the "Attach files" link below the Edit window.
 
berkeman said:
I get the angle as 63.<something> degrees. What do you get for the magnitude of the resultant?

BTW, it's best to do a sketch of this kind of problem to help in your thinking (and our checking). You can upload a sketch using the "Attach files" link below the Edit window.
For my magnitude of the resultant, the answer was R = √(100^2) + (200^2) = 223.62
 
The method is correct. The result ## R=\sqrt{100^2+200^2}=\sqrt{50000} ## should be rounded to what the answer is.
 

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