Blood can carry excess energy from the interior to the surface of the body, where the energy is dispersed in a number of ways. While a person is exercising, 0.8 kg of blood flows to the surface of the body and releases 2050 J of energy. The blood arriving at the surface has the temperature of the body interior, 37.0°C. Assuming that blood has the same specific heat capacity as water, determine the temperature of the blood that leaves the surface and returns to the interior(adsbygoogle = window.adsbygoogle || []).push({});

ok..I know thatDELTAT = Q/cm

Q= heat

since i dont have the heat..i had to find it...so i did this

Q=( CM ) (DELTAT ) = ( 4186 ) ( .8 ) ( 37.0 °C - 15.0 °C )

= 73673.6 J

now I got the heat...so i can apply this formula to find the temperature..

DELTAT = Q/cm = 73673.6 / ( 4186 ) ( .8 ) = 22 °C

but still..i keep getting it wrong... ..does any one knows what im doing wrong ??..

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# Determine the temperature of the blood/ Heat problem

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