Determine the temperature of the blood/ Heat problem

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Homework Help Overview

The discussion revolves around a heat transfer problem involving blood temperature during exercise. The original poster attempts to determine the temperature of blood returning to the interior after releasing energy at the body surface.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of heat transfer using the specific heat capacity of blood, questioning the values used and the assumptions made regarding initial and final temperatures.

Discussion Status

Participants are actively engaging with the problem, with some providing corrections and clarifications about the values used in calculations. There is a focus on understanding the relationship between energy released and temperature change, with no explicit consensus reached yet.

Contextual Notes

Some participants express confusion over the specific heat capacity value used and the initial temperature assumptions, indicating a need for clarity on these points. The problem constraints include the specific energy values given and the assumption that blood has the same specific heat capacity as water.

iceT
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Blood can carry excess energy from the interior to the surface of the body, where the energy is dispersed in a number of ways. While a person is exercising, 0.8 kg of blood flows to the surface of the body and releases 2050 J of energy. The blood arriving at the surface has the temperature of the body interior, 37.0°C. Assuming that blood has the same specific heat capacity as water, determine the temperature of the blood that leaves the surface and returns to the interior

ok..I know that DELTA T = Q/cm
Q= heat
since i don't have the heat..i had to find it...so i did this
Q=( CM ) ( DELTA T ) = ( 4186 ) ( .8 ) ( 37.0 °C - 15.0 °C )
= 73673.6 J

now I got the heat...so i can apply this formula to find the temperature..
DELTA T = Q/cm = 73673.6 / ( 4186 ) ( .8 ) = 22 °C
but still..i keep getting it wrong...:mad: :confused: ..does anyone knows what I am doing wrong ??..
 
Last edited:
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iceT said:
ok..I know that DELTA T = Q/cm
Q= heat
since i don't have the heat..i had to find it...so i did this
Q=( CM ) ( DELTA T ) = ( 4186 ) ( .8 ) ( 37.0 °C - 15.0 °C )
= 73673.6 J
What do you mean you don't have the heat? The problem stated: "0.8 kg of blood flows to the surface of the body and releases 2050 J of energy."

Where did you get the 15.0 °C ? (The final temperature of the blood is what you are trying to find.)
 
ok...so it should be
2050 / ( 4186 ) ( .8 ) = 0.612
BUT IT STILL WRONG...

ok..is it 37.612 ?
 
Last edited:
What did you get for the temperature of the cooled blood?
 
iceT said:
ok..is it 37.612 ?
You're getting closer... remember that heat is being removed from the blood.
 
Doc Al said:
You're getting closer... remember that heat is being removed from the blood.

36.388:biggrin:
 
thanx a lot Dr Al :smile: :approve:
 
Last edited:
I have a similar problem to this but I don't understand it. Where did you guys get the 4186?


(the problem I have is...Blood can carry excess energy from the interior to the surface of the body, where the energy is dispersed in a number of ways. While a person is exercising, 0.6 kg of blood flows to the surface of the body and releases 2000 J of energy. The blood arriving at the surface has the temperature of the body interior, 37.0°C. Assuming that blood has the same specific heat capacity as water, determine the temperature of the blood that leaves the surface and returns to the interior... so basically same thing, just different numbers)
 
ElikuAberts said:
Where did you guys get the 4186?
It's the specific heat capacity of water, it takes 4186J of energy to raise the temperature of 1kg of water through 1 Kelvin (or 1deg C).
You have to know/look this up, it's an experimental value.
 
  • #10
Thank you, mgb_phys! I get it now! :smile:
 

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