Rate body temperature increases given rate of heat transfer?

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SUMMARY

The discussion focuses on calculating the rate of body temperature increase in a sauna environment, where the ambient temperature is 57.0°C and the skin temperature is 37.0°C. The rate of heat transfer by radiation is determined to be 226W, using the emissivity of skin at 0.95 and a body surface area of 1.60 m². To find the rate of temperature increase in degrees Celsius per second, participants utilize the specific heat of the human body, set at 3500 J/kg*K, and apply the formula Q = mC(ΔT) alongside the relationship between power, energy, and time.

PREREQUISITES
  • Understanding of heat transfer principles, specifically radiation.
  • Familiarity with the specific heat capacity of materials, particularly the human body.
  • Knowledge of basic thermodynamic equations, including Q = mC(ΔT).
  • Ability to manipulate units in physics, particularly converting between watts and joules.
NEXT STEPS
  • Study the concept of emissivity and its impact on heat transfer.
  • Learn how to apply the specific heat formula in various thermodynamic scenarios.
  • Explore the relationship between power, energy, and time in thermal systems.
  • Investigate the effects of different ambient temperatures on human body temperature regulation.
USEFUL FOR

Students in physics or engineering courses, health professionals interested in thermoregulation, and anyone studying heat transfer in biological systems.

CrashMaverick
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Homework Statement


Suppose you walk into a sauna that has an ambient temperature of 57.0°C. Calculate the rate of heat transfer to you by radiation given your skin temperature is 37.0°C, the emissivity of skin is 0.95, and the surface area of your body is 1.60 m2.

I solved this first part and found the answer to be 226W

If all other forms of heat transfer are balanced (the net heat transfer is zero), at what rate will your body temperature increase (degC/s) if your mass is 68.0 kg?

Note from instructor:

You can take the specific heat of the human body as:

c = 3500 J/kg*K

Homework Equations



Q = mC(ΔT)? Not entirely sure where to start really

m = mass
C = specific heat
ΔT = change in temperature

The Attempt at a Solution


So if you multiple C by m and ΔT(in kelvin) you end up with units of Joules right?
1 joule / 1 sec = 1 watt, I figure there is something I can do there, but I'm not sure what. The thing that is throwing me off is the units of degrees Celsius per second.

I've been staring at this problem for a couple hours and I'm sure I'm overlooking a very simple thing, any help is appreciated.
 
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Your relevant equation is relevant. The Q does indeed stand for energy (in Joules).

The other equation you need is Power = Energy/Time.

Put the two equations together and rearrange so that on one side you have the quantities temperature and time as those are the units specified for the answer.

Sorry for all the edits I made to this repy.
 

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