Determine the unit tangent vector

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The discussion centers on the justification for the equation |dr/dt| = ds/dt in the context of vector differentiation. It is clarified that ds is equivalent to the magnitude of the differential vector dr, which supports the relationship. Participants confirm that the steps leading to this conclusion are straightforward. The focus remains on understanding the mathematical reasoning behind the equality. This clarification aids in comprehending the derivation of the unit tangent vector.
chwala
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Homework Statement
see attached
Relevant Equations
vector differentiation
1644910436015.png


I need a justification that ##|\dfrac {dr}{dt}|##=##\dfrac {ds}{dt}## cheers guys... all the other steps are easy and clear to me...
 
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chwala said:
Homework Statement:: see attached
Relevant Equations:: vector differentiation

View attachment 297138

I need a justification that [Modulus ##\big | \dfrac {dr}{dt} \big |##=##\dfrac {ds}{dt}##] cheers guys... all the other steps are easy and clear to me...
We have ##ds \equiv |d\vec r|##.
 
Aaaaah Perok cheers!
PeroK said:
We have ##ds \equiv |d\vec r|##.
 

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