Determine torque required to accelerate the flywheel

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SUMMARY

The discussion focuses on calculating the torque required to accelerate a solid disk flywheel with a diameter of 500 mm and a mass of 60 kg from rest to 250 rpm over 6 revolutions. The moment of inertia (I) is calculated using the formula I = m * r², resulting in I = 3.75 kg·m². The angular velocity is converted to radians per second (26.18 rad/sec), and the relationship τ = Iα is emphasized to find the required torque. Participants highlight the importance of using correct units and applying kinematic equations for rotational motion.

PREREQUISITES
  • Understanding of rotational dynamics and torque calculations
  • Familiarity with moment of inertia formulas for solid disks
  • Knowledge of angular velocity and angular acceleration concepts
  • Ability to convert between RPM and radians per second
NEXT STEPS
  • Learn how to derive the moment of inertia for different shapes, including solid disks and cylinders
  • Study the application of kinematic equations in rotational motion
  • Explore the relationship between torque, angular acceleration, and moment of inertia
  • Practice converting between RPM and radians per second for various rotational systems
USEFUL FOR

Mechanical engineers, physics students, and anyone involved in designing or analyzing rotational systems, particularly in energy recovery devices.

em3
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Homework Statement


A solid disk of diameter equal to 500 mm and a mass of 60 kg is to be used as a flywheel in an energy recovery device. Determine the torque required to accelerate the rotation of the flywheel, about its axis, from rest to 250 rpm in 6 revolutions.

Homework Equations


[/B]
τ=Iα

The Attempt at a Solution



r = 0.25

I = m *r2
I= 60 * 0.252
I = 3.75

3.75 * 26.17993
=98I'm not really sure what to do, I can't get the correct answer.
 
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It helps if you use units when doing your calculations. Then you might realize that 26.17 rad/sec is the angular velocity (equivalent to 250 rpm), not acceleration. It took 6 seconds to get up to this speed. How can you use this information to get angular acceleration?
 
em3 said:

Homework Statement


A solid disk of diameter equal to 500 mm and a mass of 60 kg is to be used as a flywheel in an energy recovery device. Determine the torque required to accelerate the rotation of the flywheel, about its axis, from rest to 250 rpm in 6 revolutions.

Homework Equations


[/B]
τ=Iα

The Attempt at a Solution



r = 0.25

I = m *r2
Is that the correct formula for the moment of inertia of a disk?
I= 60 * 0.252
I = 3.75
What are the units?
3.75 * 26.17993
=98
What were you trying to calculate there? Looks like you might be multiplying the angular velocity by your moment of inertia, but since there are no units shown we can't be sure.

The kinematic formulas that apply to linear motion can be applied to rotational motion if you substitute the analogous terms. So:

mass ⇔ moment of inertia,
velocity ⇔ angular velocity,
acceleration ⇔ angular acceleration,
force ⇔ torque,
distance ⇔ angular distance.

If you relate the rotational motion terms to those of linear motion you're given a mass (moment of inertia) , a final speed (angular velocity), and the distance covered (number of revolutions).

Sort out your moment of inertia by finding the correct formula for a solid cylinder (disk), then look at your SUVAT equations to see if you can find the required torque from what you've been given.
 

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