What torque must be applied to this flywheel?

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Homework Help Overview

The problem involves calculating the torque required to accelerate a solid steel flywheel attached to a chainsaw. The flywheel has a mass of 1.5 kg and a diameter of 10 cm, and it needs to reach an angular velocity of 4.0 revolutions per second within 2.0 seconds. The original poster attempts to apply the relationship between angular acceleration, torque, and moment of inertia.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to convert revolutions per second to radians per second for proper calculations. There are questions about the conversion process and the correct application of formulas related to torque and angular acceleration.

Discussion Status

Participants are actively engaging in clarifying the conversion of units and discussing the calculations involved. Some guidance has been offered regarding the correct units for torque, and there is acknowledgment of the method used by the original poster, though no consensus on the final answer has been reached.

Contextual Notes

Participants are navigating through the conversion of units and ensuring the correct application of physics principles, with some uncertainty about the calculations and the final answer.

dancer_smiley
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Here is the problem: A chainsaw is started by pulling on a rope that is attached to a solid steel flywheel. Assume that the wheel has a mass of 1.5 kg that is completely distributed along the outside edge, and it has a diameter of 10 cm. It starts at rest and must accelerate to 4.0 rev/s in 2.0 seconds in order to start the motor. What torque must be applied to the flywheel?

Equation I used: Angular Acceleration = Torque/Moment of Inertia

Here is my attempt: (1.5 kg)(.05 m)^2 (4.0 rev/s / 2.0 s) = .0075

I don't think this is the correct answer, but I have no idea how to solve this question...
 
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You need to convert rev/s to rad/s for this to work.
 
Do I divide my answer by 2(pi)rad to do that?
 
1 revolution = 2pir

You can use the ratio (1 rev)/(2pir) or (2pir)/( 1 rev) to convert from revolutions to radians or vice versa. You have revs and you want to convert to radians so multiply through the ratio that will cancel out the revs.
 
thepatient said:
1 revolution = 2pir

You can use the ratio (1 rev)/(2pir) or (2pir)/( 1 rev) to convert from revolutions to radians or vice versa. You have revs and you want to convert to radians so multiply through the ratio that will cancel out the revs.
One revolution is not 2πr. One revolution is 2π radians without the "r". Then one rev/s is 2π rad/s and x revolutions per second is x*2π rad/s.
 
kuruman said:
One revolution is not 2πr. One revolution is 2π radians without the "r". Then one rev/s is 2π rad/s and x revolutions per second is x*2π rad/s.


Yes. XD 2pi = 1 rev. I don't know what I was thinking.
 
I multiplied .0075*(2pi)
So that makes my answer .047123?
Is that the correct answer for the problem?
 
What units do I use? Is it meters?
 
The units of torque are Newton-meters.
 
  • #10
So my answer is 4.7x10^-2 Nm? Is this correct?
 
  • #11
dancer_smiley said:
So my answer is 4.7x10^-2 Nm? Is this correct?
The method is correct and the answer should be if you plugged in the numbers correctly.
 
  • #12
Thank you so much for your help! :)
 

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