- Homework Statement:
- I'm not sure how to start question b.) I understand that I have the denominator powered to the square, it's function "grows faster" than the function in the numerator.
- Relevant Equations:
Does it grow? What happens to e-t as t increases?it's function "grows faster" than the function in the numerator.
So you'll have lim t---> infinite , the function in the denominator will grow faster, so as t grows, P'(x) approaches zero. I believe another way to see this is to note that for t---> inf, P(x)---> 24, therefore reaching a constant value, with zero rate of change. My rate would be zero, right?I am not seeing this sign mistake and think your answer is correct. However it was unnecessary to use the full formula for derivative of u(x)/v(x) - since u is just a constant you only needed that for 1/v(x).
You are not thinking about the rest in quite the right way. What happens to e-t as t increases and as it becomes very large? Alternatively you get something that might be mere self-evident to you if you divide top and bottom of the fraction by e-t.