Determing Spring Constant by Graphing

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The discussion revolves around determining the spring constant from a lab experiment involving a spring and a wooden cylinder. The user collected data on the height achieved by the projectile after releasing it with varying masses added. They derived an equation for the spring constant, K, but are unsure how it relates to the required graph of x0²/m versus hf - h0. The user believes their energy conservation approach is valid but seeks clarification on the connection between their derived equation and the graphing instructions. Ultimately, the goal is to confirm the correct method for deriving the spring constant using the provided data.
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Homework Statement


In class, we did a lab that consisted of putting a small wooden cylinder in a pipe that contained a spring, pushing it down on the spring and locking it in, then unlocking it which allowed it to launch straight up. We then would add fishing weights to the block to increase the mass and did 3 trials with each mass. This is my collected data:

Constant Values: h0 = .258 m, x0 = .022 m, xf = .000 m, V0 = 0 m/s, Vf = 0 m/s

Height of uncompressed projectile
Trials 1-3: m = .0228 kg, hf (avg) = 1.367 m
Trials 4-6: m = .0280 kg, hf (avg) = 1.304 m
Trials 7-9: m = .0329 kg, hf (avg) = 1.076 m
Trials 10-12: m = .0380 kg, hf (avg) = 0.951 m
Trials 13-15: m = .0424 kg, hf (avg) = 0.860 m

It now asks me to derive an equation for the spring constant of the projectile launcher based on the data I have. I came up with this: K = 2Us/X02 = 2(.5m2ahfavg - mgh0) / X02

Then it says Your goal for the lab is to determine the spring constant. If you graph your data with x02/m on the x-axis and hf-h0 on the y-axis you should get a straight line with a slope of _____ and a y-intercept of _____.

Homework Equations



V2 = V02 + 2aΔy
Us = .5Kx2

The Attempt at a Solution



As I said above, I derived K = 2Us/X02 = 2(.5m2ahfavg - mgh0) / X02

I tested it with some old data in my notes (that I knew K for) and it worked... but now that I see it wants me to graph x02/m on the x-axis and hf-h0 on the y-axis, I feel like I did it wrong because I can't see where those values became relevant.

So my question is did I derive that equation correctly? And how does it relate to what it wants me to graph? Thank you for your help!
 
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I would think that all the energy stored in the spring

Us = 1/2 K X^{2}_{o}

would be converted to the potential energy of the block at the top

Ub = mg(hf - ho)

so that

hf - ho = ( \frac{K}{2g} ) \frac{X^{2}_{o}}{m}
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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