Determing where function is differentiable (Complex Analysis)

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The function f(x + iy) = 1/(x + i3y) is analyzed for differentiability using the Cauchy-Riemann equations. It is established that the equations are not satisfied everywhere, indicating potential points of differentiability. The discussion reveals that differentiability occurs at points where the equations hold, specifically at x = 3y and xy = 3xy. However, further analysis shows that these conditions lead to the origin (0 + 0i), where the function is actually undefined. Consequently, the conclusion is that the function is differentiable nowhere.
scothoward
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Homework Statement


Determine where the function f has a derivative, as a function of a complex variable:

f(x +iy) = 1/(x+i3y)


The Attempt at a Solution



I know the cauchy-riemann is not satisfied, so does that simply mean the function is not differentiable anywhere?
 
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No. Where Cauchy-Riemann is satisfied, the function is differentiable. There could be some places. Are there?
 
Hmm I was thinking, maybe I could take the partials of U and V (Cauchy-Riemann) equate them, and find out what x,y have to be in order for the equations to be satisfied. Am I on the right track?
 
Yes, if CR is satisfied at a point, then the function is differentiable at that point. That's where CR comes from.
 
Last edited:
Alright, so doing the partials and equating I get

x = 3y and
xy = 3xy

But, I am a little confused on what to do from here.

Thanks for the help
 
Thinking about it a little more, would this mean when x = 3y, the function is differentiable and when either x=0, y=0, the function is differentiable? Or is my thinking wrong?
 
IF that's right then putting the first equation into the second gives 3y^2=9y^2, so y=0. If y=0 then x=0. So differentiable only at 0+0i.
 
Thanks for the help Dick!

Just to clarify one more thing. Presuming that I did calculate the paritals right and that leads to 0 + i0, wouldn't that lead to the original function being undefined? As a result, wouldn't the function be differentiable no where?
 
Very astute, scothoward. I was on my way to missing that.
 

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