Determining a trigonometric limit

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Bunny-chan
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Homework Statement


Calculate the following limit:

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Homework Equations

The Attempt at a Solution


I don't know how to proceed with this. I've tried to multiply by the conjugate, and to simplify the expression [itex](x+\pi)[/itex] to [itex]u[/itex], but I wasn't very successful. To what kind of algebric device I could resort to? Or is there other way to deduce the limit?
 
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Bunny-chan said:

Homework Statement


Calculate the following limit:

View attachment 203337

Homework Equations

The Attempt at a Solution


I don't know how to proceed with this. I've tried to multiply by the conjugate, and to simplify the expression [itex](x+\pi)[/itex] to [itex]u[/itex], but I wasn't very successful. To what kind of algebric device I could resort to? Or is there other way to deduce the limit?
The problem as written is continuous at ##x=0##, so just plug it in. Or if both terms in the denominator are supposed to be cube roots, try L'Hospital's rule.
 
Bunny-chan said:

Homework Statement


Calculate the following limit:

View attachment 203337

Homework Equations

The Attempt at a Solution


I don't know how to proceed with this. I've tried to multiply by the conjugate, and to simplify the expression [itex](x+\pi)[/itex] to [itex]u[/itex], but I wasn't very successful. To what kind of algebric device I could resort to? Or is there other way to deduce the limit?
I assume you meant to write ##\sqrt[3]{x+\pi}## instead of ##3 \sqrt{x+\pi}## in the denominator. If you do not want to (or are unable to) use calculus, use instead the algebraic identity ##a^3-b^3 = (a-b)(a^2+a b + b^2)## for appropriate ##a## and ##b##.