Trigonometric Limit Problem: Finding the Limit as x Approaches 0

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SUMMARY

The limit as x approaches 0 of the expression 3sin(4x) / sin(3x) can be solved using the fundamental limit lim as x -> 0 of sin(x) / x = 1. By applying the identity sin(2x) = 2sin(x)cos(x) to rewrite sin(4x) as 2sin(2x)cos(2x), the problem simplifies significantly. This manipulation leads to a well-known limit that can be easily evaluated, confirming that the limit exists and can be computed directly.

PREREQUISITES
  • Understanding of trigonometric identities, specifically sin(2x) = 2sin(x)cos(x)
  • Familiarity with limits in calculus, particularly lim as x -> 0 of sin(x) / x = 1
  • Basic algebraic manipulation skills for simplifying expressions
  • Knowledge of the behavior of sine functions near zero
NEXT STEPS
  • Study the derivation and applications of the limit lim as x -> 0 of sin(x) / x = 1
  • Explore advanced trigonometric identities and their proofs
  • Learn about L'Hôpital's Rule for evaluating indeterminate forms
  • Practice solving similar limit problems involving trigonometric functions
USEFUL FOR

Students studying calculus, particularly those focusing on limits and trigonometric functions, as well as educators seeking examples for teaching limit evaluation techniques.

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Homework Statement


find the limit as x approaches 0 of 3sin4x / sin3x


Homework Equations


sin2x = 2sinxcosx
lim as x ->0 of sinx / x =1


The Attempt at a Solution


sin4x = 2 sin2x cos2x
 
Physics news on Phys.org
Divide and multiply both numerator and denominator with the angles of resective sin .
You will get one famous limit , after that its a breeze :cool:
 

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