How Do You Solve This Trigonometric Limit Problem?

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Homework Help Overview

The discussion revolves around evaluating the limit of a trigonometric expression as \(x\) approaches 0, specifically \(\lim_{x \to 0} \frac{\tan(\cos(4x) - 1)}{3x \sin(\frac{4}{3} x)}\). The subject area includes trigonometric limits and properties of trigonometric functions near zero.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the behavior of trigonometric functions as \(x\) approaches 0, discussing approximations for \(\sin(x)\), \(\cos(x)\), and \(\tan(x)\). There is an attempt to manipulate the limit expression using these properties, with some questioning how to apply these approximations effectively.

Discussion Status

The discussion is active, with participants providing insights into the properties of trigonometric functions for small values of \(x\). Some guidance has been offered regarding the approximations that can be used in the limit evaluation, and there is a recognition of the relevance of these properties to the problem at hand.

Contextual Notes

Participants express uncertainty about the specific properties of trigonometric functions that apply to the limit problem, indicating a need for clarification on how these properties relate to the limit evaluation.

songoku
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Homework Statement


\lim_{x \to 0} \frac{tan (cos 4x - 1)}{3x ~ sin (\frac{4}{3} x)}


Homework Equations


limit for trigonometry


The Attempt at a Solution


can I do it like this:

\frac{tan (cos 4x - 1)}{3x ~ sin (\frac{4}{3} x)}

= \frac{- tan (2 sin^{2} 2x)}{3x ~ sin (\frac{4}{3} x)}

and then using the property of trigonometry limit, it becomes:

= \frac{-2 . 4}{3 . \frac{4}{3}}

=-2
 
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What do you know about sin(x), cos(x) and tan(x) when x is very small?
 
jing2178 said:
What do you know about sin(x), cos(x) and tan(x) when x is very small?

I am not sure what you mean, maybe like this:

a. when x is very small (close to zero):
the value of sin x is close to 0
the value of cos x is close to 1
the value of tan x is close to 0

or

b. when x is very small (close to zero):
sin x ≈ x
cos x ≈ 1 - 1/2 x2 ≈ 1
tan x ≈ x

but I still don't know what the properties related to the question
 
songoku said:
I am not sure what you mean, maybe like this:

a. when x is very small (close to zero):
the value of sin x is close to 0
the value of cos x is close to 1
the value of tan x is close to 0

or

b. when x is very small (close to zero):
sin x ≈ x
cos x ≈ 1 - 1/2 x2 ≈ 1
tan x ≈ x

but I still don't know what the properties related to the question

You're looking to use the properties of b.

If \cos(x)\approx 1-x^2/2 then what is \cos(4x) approximately equal to?

What's \sin(4x/3) approximately equal to?

Finally, you'll need to also convert the tan function as well in the same fashion.
 
Mentallic said:
You're looking to use the properties of b.

If \cos(x)\approx 1-x^2/2 then what is \cos(4x) approximately equal to?

What's \sin(4x/3) approximately equal to?

Finally, you'll need to also convert the tan function as well in the same fashion.

Oh I see. I don't know before that the properties can be used in limit as well.

Thanks a lot for all the help
 

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