1. The problem statement, all variables and given/known data A 2.0 kg block of wood slides over a horizontal surface and comes to rest in 2.5 s. If its initial velocity was 9.0 m/s, what is the coefficient of kinetic friction? 2. Relevant equations rho=mv change in rho=F*change in t Force of friction = mu*Force normal Force normal=mg 3. The attempt at a solution rho=(2.0 kg)(9.0 m/s)=18 kg*m/s 18 kg*m/s=Force of friction(2.5 s) Force of friction=7.2 mu*Force normal=7.2 mu(2.0 kg)(9.80 m/s squared)=7.2 mu=0.37 I don't know what the correct answer to this question is and I potentially may not know until the day of my exam. Can anyone tell me if I'm doing this correctly or if I'm missing something? I really appreciated it!