Find the kinetic coefficient of friction (mu)

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SUMMARY

The discussion focuses on calculating the kinetic coefficient of friction (μ) for an elevator with a total mass of 1,800 kg (1,000 kg elevator plus 800 kg load) moving at a velocity of 3 m/s over a distance of 0.01 km. The net work done is given as 13,640 J. The equation used is Force of friction = (m)(μ)(gravity), leading to the equation 9.8 = (μ)(17,640), which simplifies to μ = 0.001. The participants emphasize the need for clarity regarding the velocity and distance parameters in the problem statement.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concept of work and energy
  • Basic knowledge of frictional forces
  • Ability to manipulate algebraic equations
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Abhishek Gupte
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Homework Statement


A 1.0x10^3 kg elevator carries a maximum load of 800kg
Velocity = 3m/s
Distance = .01km
Net work = 13640J

Homework Equations


Force of friction = (m)(mu)(gravity)

The Attempt at a Solution


Gravity = friction
9.8 = (mu)(17640)
.001 = mu
 
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Please state the whole question. Velocity at what stage? Distance of what? ...
 

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